Find all ordered pairs of real numbers ($x,y$) for which
$$(1+x)(1+x^{2})(1+x^{4})=1+y^{7}$$
$$(1+y)(1+y^{2})(1+y^{4})=1+x^{7}$$
I am not sure on how to solve this. There is a clear symmetry in the problem. Also on expanding the LHS, we will get the GP
$$1+x+x^2+x^3+x^4+x^5+x^6+x^7=1+y^7$$ and similarly for the second equation. I tried manipulating the two equations and factorise them but I was unsuccesful. Any help would be much appreciated. Thanks a lot
Algebra question to find all ordered pairs to a set of equations
algebra-precalculuscontest-mathpolynomialssymmetric-polynomialssymmetry
Best Answer
Observe that
$$ y^ 8 - x^8 = (y - x) + (y^ 7 - x^7) + xy (x^6 - y^6)$$
$\qquad$ If $x < y < 0 $, then the LHS is negative, but each term on the RHS is positive. Hence contradiction. Likewise if $ y < x < 0 $.
Note: A very common misconception when solving symmetric system of equations is thinking that all solutions to $x = f(y), y = f(x)$ are of the form $ y = x$.
In fact, what we truly require is $ f(f(x)) = x, y = f(x)$.
This is most obvious when looking at self-inverse functions like $f(x) = x, f(x) = -x, f(x) = \frac{1}{x}$. However, it's not about the function, but about the "self-inverse" point, namely $f(x) = f^{-1} (x)$.