$\{a_n\}$ converges. Can $\{|a_n|\}$ diverge?
My try:
$\{a_n\}$ converges $\Longleftrightarrow$ $\exists l\in R,\lim_{n\to\infty} a_n = l$
$\lim_{n\to\infty} a_n = l \Longrightarrow \lim_{n\to\infty} |a_n| = |\lim_{n\to\infty} a_n| = |l|$
And now we prove the previous line:
$\lim_{n\to\infty} a_n = l \Longleftrightarrow \forall\epsilon > 0 , \exists n_o\in N , \forall n>n_0 : |a_n-l|<\epsilon$
We know by the triangle inequality that:
$\left||a_n|-|l|\right|\leq |a_n-l|<\epsilon$
Then:
$\forall\epsilon > 0 , \exists n_o\in N , \forall n>n_0 : ||a_n|-|l||<\epsilon\Longleftrightarrow \lim_{n\to\infty} |a_n| = |l| $
This means that the answer to the question is NO
I am aware that this is similar to this other post , but it didnt solve my problem.
Best Answer
As an alternative, suppose by contradiction that $|a_n|$ diverges therefore since
$|a_n|=a_n$ for $a_n\ge 0$
$|a_n|=-a_n$ for $a_n< 0$
we have that $a_n$ doesn’t converge.