A question about discriminant

algebra-precalculusintuition

Lately I have been trying to think about equations in terms of graphs a lot and I stumbled on equation for solutions of quadratic equation, and I could not understand everything about it.

I can understand that $ \frac{-b}{2a}$ is supposed to result in the lowest point of the graph, but I can't quite wrap the head around how $ \sqrt{({\frac{b}{2a}})^2 – \frac{c}{a}} $ results in the distances of the zeroes from that lowest point. I had like some intuition behind what goes in there. Thanks!

Best Answer

Look at the following visual:

enter image description here

Let, $OA=\alpha$ and $OB=\beta$

By power of point for a circle, the length of the red line $=\sqrt{OA\cdot OB}=\sqrt{\alpha\cdot \beta}=\sqrt\frac ca$

Also, by Pythagoras Theorem, the length of the red line is $\sqrt{OC^2-AC^2}=\sqrt{(\frac{\alpha +\beta}{2})^2-AC^2}=\sqrt{(\frac{-b}{2a})^2-AC^2}$

Equate both the expressions to get your desired result.

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