I want to create 3D view. and I am using OpenLayers.
Is it Possible?
[GIS] How to create 3D globe view with OpenLayers
3dopenlayers-2
Related Solutions
If you only have two points on a line you may have to create more vertices and then reproject these to EPSG:4326 and back again to create something similar to the Google example.
There is an OpenLayers example of Great Circle lines here. The source code for the algorithms is also online.
There is a getGeodesicArea function on OpenLayer polygons, and geometry collections. There is also a getGeodesicLength function. These algorithms are implemented based on the following (according to the docs):
Robert. G. Chamberlain and William H. Duquette, “Some Algorithms for Polygons on a Sphere”, JPL Publication 07-03, Jet Propulsion Laboratory, Pasadena, CA, June 2007 http://trs-new.jpl.nasa.gov/dspace/handle/2014/40409
Looking at the sourcecode it reprojects points to 4326, and then uses the OpenLayers.Util.distVincenty function to calculate the distance between points on the surface of an ellipsoid (the earth).
getGeodesicLength: function(projection) {
var geom = this; // so we can work with a clone if needed
if(projection) {
var gg = new OpenLayers.Projection("EPSG:4326");
if(!gg.equals(projection)) {
geom = this.clone().transform(projection, gg);
}
}
var length = 0.0;
if(geom.components && (geom.components.length > 1)) {
var p1, p2;
for(var i=1, len=geom.components.length; i<len; i++) {
p1 = geom.components[i-1];
p2 = geom.components[i];
// this returns km and requires lon/lat properties
length += OpenLayers.Util.distVincenty(
{lon: p1.x, lat: p1.y}, {lon: p2.x, lat: p2.y}
);
}
}
// convert to m
return length * 1000;
}
For polygons areas, the algorithm is in the LinearRing source, and uses the earth's radius of 6378137 and geometry to calculate the geodesic area.
getGeodesicArea: function(projection) {
var ring = this; // so we can work with a clone if needed
if(projection) {
var gg = new OpenLayers.Projection("EPSG:4326");
if(!gg.equals(projection)) {
ring = this.clone().transform(projection, gg);
}
}
var area = 0.0;
var len = ring.components && ring.components.length;
if(len > 2) {
var p1, p2;
for(var i=0; i<len-1; i++) {
p1 = ring.components[i];
p2 = ring.components[i+1];
area += OpenLayers.Util.rad(p2.x - p1.x) *
(2 + Math.sin(OpenLayers.Util.rad(p1.y)) +
Math.sin(OpenLayers.Util.rad(p2.y)));
}
area = area * 6378137.0 * 6378137.0 / 2.0;
}
return area;
},
The main problem I had with the circle was that I only had one reference coordinate, and there was no inbuilt way in OpenLayers to create a circle around this point apart from on a Cartesian plane. However with the OpenLayers.Util.distVincenty function it was relatively easy to calculate these.
you need to assign the styles of sld to vector.
- Create a sld format object using OpenLayers.Format.SLD and Openlayers.Request.GET
assign the style to vector using style or stylemap
var format = new OpenLayers.Format.SLD(); OpenLayers.Request.GET({ url: "yoursldfile.sld", success: sldparser }); function sldparser(req) { sld = format.read(req.responseXML || req.responseText); styles = sld.namedLayers.interpreted.userStyles[0]; building_vec.styleMap.styles.default = styles; }
Best Answer
Use Cesium. It is being used in OpenLayers 3.