[GIS] How to change this exif data into long and lat

coordinate systemgpsimagelinux

I've been using ImageMagick in a Linux terminal but I'm not sure how to read the coordinates it's giving me.
enter image description here

If you can't see the picture, the data is:

Properties:
    date:create: 2020-05-21T12:33:53+01:00
    date:modify: 2020-05-21T12:33:53+01:00
    exif:ExifOffset: 38
    exif:GPSDateStamp: 2015:12:09
    exif:GPSInfo: 68
    exif:GPSLatitude: 23/1, 21/1, 35928/625
    exif:GPSLatitudeRef: N
    exif:GPSLongitude: 98/1, 0/1, 14886/625
    exif:GPSLongitudeRef: W
    exif:GPSMapDatum: WGS-84
    exif:GPSTimeStamp: 11/1, 21/1, 42/1
    exif:GPSVersionID: 2, 2, 0, 0
    exif:PixelXDimension: 1000
    exif:PixelYDimension: 660
    jpeg:colorspace: 2
    jpeg:sampling-factor: 2x2,1x1,1x1
    signature: 1c3ce39629e01d4cf738f153e810a468264c1dc110a9af7ebe37b83e81969ee3
    xmp:GPSLatitude: 23,21.958080N
    xmp:GPSLongitude: 98,0.396960E
    xmp:GPSMapDatum: WGS-84
    xmp:GPSTimeStamp: 2015-12-09T11:21:42.37Z
    xmp:GPSVersionID: 2.2.0.0
    xmp:PixelXDimension: 1000
    xmp:PixelYDimension: 660

Best Answer

The coordinates are clearly spelled out in your screen capture.

Latitude = 23° 21.958080N in DD MM:MM (3/1, 21/1, 35928/625 is this same value in DMS) or -23.365968° in Decimal Degrees

Longitude = 98° 0.396960E in DD MM:MM (98/1, 0/1, 14886/625 is this same value in DMS) or 98.023283° in Decimal Degrees.

Your reference system is WGS 1984

You have 1000 pixels in the X dimension (Longitude)

You have 660 pixels in the Y dimension (Longitude)

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