Null Hypothesis: LOG_AUSTRIA has a unit root
Exogenous: Constant
Lag Length: 1 (Automatic - based on SIC, maxlag=29)
t-Statistic Prob.*
Augmented Dickey-Fuller test statistic 1.765602 0.9997
Test critical values: 1% level -3.432059
5% level -2.862181
10% level -2.567155
*MacKinnon (1996) one-sided p-values.
Augmented Dickey-Fuller Test Equation
Dependent Variable: D(LOG_AUSTRIA)
Method: Least Squares
Date: 07/17/13 Time: 18:55
Sample (adjusted): 3 3450
Included observations: 3448 after adjustments
Variable Coefficient Std. Error t-Statistic Prob.
LOG_AUSTRIA(-1) 0.000659 0.000373 1.765602 0.0776
D(LOG_AUSTRIA(-1)) 0.053321 0.017030 3.131112 0.0018
C -0.003183 0.002040 -1.560515 0.1187
R-squared 0.003923 Mean dependent var 0.000428
Adjusted R-squared 0.003345 S.D. dependent var 0.010612
S.E. of regression 0.010595 Akaike info criterion -6.256058
Sum squared resid 0.386693 Schwarz criterion -6.250711
Log likelihood 10788.44 Hannan-Quinn criter. -6.254148
F-statistic 6.784764 Durbin-Watson stat 2.000233
Prob(F-statistic) 0.001146
Solved – How to interpret results from unit root tests with intercept
eviewstime series
Best Answer
For the interpretation of
Eviews
output, just focus on top part. The lower one shows how theEviews
runs the regression.Eviews
runs the regression in first difference form, so the null is coefficient onLOG_AUSTRIA(-1)
is zero which means that there is an unit root.The alternate hypothesis is that it is less than zero, i.e., there is no unit root.Your test statistic 1.765602 is greater than critical value -2.567155 at 10%. So, you accept the null that there is an unit root (see p=0.999). To reject the null at 10 %, p<=0.10 (test statistic should be less than -2.567155), to reject the null at 5% (test statistic should be less than-2.862181) p<=0.05, and to reject the null at 1%,(test statistic should be less than-3.432059) p<=0.01.