I think the simplest way to look at it is to note that ARMA and similar models are designed to do different things than multi-level models, and use different data.
Time series analysis usually has long time series (possibly of hundreds or even thousands of time points) and the primary goal is to look at how a single variable changes over time. There are sophisticated methods to deal with many problems - not just autocorrelation, but seasonality and other periodic changes and so on.
Multilevel models are extensions from regression. They usually have relatively few time points (although they can have many) and the primary goal is to examine the relationship between a dependent variable and several independent variables. These models are not as good at dealing with complex relationships between a variable and time, partly because they usually have fewer time points (it's hard to look at seasonality if you don't have multiple data for each season).
The residuals from gls
will indeed have the same autocorrelation structure, but that does not mean the coefficient estimates and their standard errors have not been adjusted appropriately. (There's obviously no requirement that $\Omega$ be diagonal, either.) This is because the residuals are defined as $e = Y - X\hat{\beta}^{\text{GLS}}$. If the covariance matrix of $e$ was equal to $\sigma^2\text{I}$, there would be no need to use GLS!
In short, you haven't done anything wrong, there's no need to adjust the residuals, and the routines are all working correctly.
predict.gls
does take the structure of the covariance matrix into account when forming standard errors of the prediction vector. However, it doesn't have the convenient "predict a few observations ahead" feature of predict.Arima
, which takes into account the relevant residuals at the end of the data series and the structure of the residuals when generating predicted values. arima
has the ability to incorporate a matrix of predictors in the estimation, and if you're interested in prediction a few steps ahead, it may be a better choice.
EDIT: Prompted by a comment from Michael Chernick (+1), I'm adding an example comparing GLS with ARMAX (arima) results, showing that coefficient estimates, log likelihoods, etc. all come out the same, at least to four decimal places (a reasonable degree of accuracy given that two different algorithms are used):
# Generating data
eta <- rnorm(5000)
for (j in 2:5000) eta[j] <- eta[j] + 0.4*eta[j-1]
e <- eta[4001:5000]
x <- rnorm(1000)
y <- x + e
> summary(gls(y~x, correlation=corARMA(p=1), method='ML'))
Generalized least squares fit by maximum likelihood
Model: y ~ x
Data: NULL
AIC BIC logLik
2833.377 2853.008 -1412.688
Correlation Structure: AR(1)
Formula: ~1
Parameter estimate(s):
Phi
0.4229375
Coefficients:
Value Std.Error t-value p-value
(Intercept) -0.0375764 0.05448021 -0.68973 0.4905
x 0.9730496 0.03011741 32.30854 0.0000
Correlation:
(Intr)
x -0.022
Standardized residuals:
Min Q1 Med Q3 Max
-2.97562731 -0.65969048 0.01350339 0.70718362 3.32913451
Residual standard error: 1.096575
Degrees of freedom: 1000 total; 998 residual
>
> arima(y, order=c(1,0,0), xreg=x)
Call:
arima(x = y, order = c(1, 0, 0), xreg = x)
Coefficients:
ar1 intercept x
0.4229 -0.0376 0.9730
s.e. 0.0287 0.0544 0.0301
sigma^2 estimated as 0.9874: log likelihood = -1412.69, aic = 2833.38
EDIT: Prompted by a comment from anand (OP), here's a comparison of predictions from gls
and arima
with the same basic data structure as above and some extraneous output lines removed:
df.est <- data.frame(list(y = y[1:995], x=x[1:995]))
df.pred <- data.frame(list(y=NA, x=x[996:1000]))
model.gls <- gls(y~x, correlation=corARMA(p=1), method='ML', data=df.est)
model.armax <- arima(df.est$y, order=c(1,0,0), xreg=df.est$x)
> predict(model.gls, newdata=df.pred)
[1] -0.3451556 -1.5085599 0.8999332 0.1125310 1.0966663
> predict(model.armax, n.ahead=5, newxreg=df.pred$x)$pred
[1] -0.79666213 -1.70825775 0.81159072 0.07344052 1.07935410
As we can see, the predicted values are different, although they are converging as we move farther into the future. This is because gls
doesn't treat the data as a time series and take the specific value of the residual at observation 995 into account when forming predictions, but arima
does. The effect of the residual at obs. 995 decreases as the forecast horizon increases, leading to the convergence of predicted values.
Consequently, for short-term predictions of time series data, arima
will be better.
Best Answer
The two models model somewhat different things.
arima(... , xreg = ...)
calculates a regression onxreg
, modeling its errors as an ARIMA process. Note that this is not the same as an ARIMAX model, and that this also applies toArima()
andauto.arima()
.gls(..., correlation=corARMA(p,q))
calculates a generalized linear model, where the correlation structure of your errors follows an ARMA(p,q) process.The ideas are of course similar, but the actual models are somewhat different. I find the
arima()
model easier to understand. It would be interesting to compare the coefficients on both the fixed regressors and the ARIMA models for the errors resp. their correlation.Given that both models have the same complexity (as in number of parameters, as long as ARMA orders are the same), I'd go with the better fitting one. (But remember that you can't compare AICs calculated by functions in different packages, as AIC is only defined up to a constant, which can definitely differ between packages.)