How to give a node the shape of an upside-down triangle (base at top)?
I tried the following:
triangle/.style = { regular polygon, regular polygon sides=3, rotate=180}
But I don't want the text rotated.
[Tex/LaTex] Upside-down triangle as node shape
shapestikz-pgf
Related Solutions
The source of the difficulty is that ellipses are constructed in a particular way in TikZ. They are paths that start from the x-axis and proceed counter-clockwise around their centre. The vast majority of the time, the exact parametrisation doesn't matter. You appear to have found the one situation where it does!
In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
#2%
\pgf@xa=-\pgf@x
\origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother
\tikzset{
reversed ellipse/.style={
ellipse,
reverse the ellipse%
},
reverse the ellipse/.code={
\let\pgfpathellipse=\revpgfpathellipse
}
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
draw,
postaction={
decorate,
decoration={
markings,
mark=at position 1 with {
\arrow[line width=5pt,blue]{>}
}
}
}
] at (0,0) {hello world};
\node[reversed ellipse,
draw,
postaction={
decorate,
decoration={
markings,
mark=at position 1 with {
\arrow[line width=5pt,blue]{>}
}
}
}
] at (0,-2) {hello world};
\end{tikzpicture}
\end{document}
Here's the result:
(the arrow got clipped, but you can see where it lies)
I think this is small enough via kerning (which makes the box quite smaller horizontally) :-)
\documentclass[tikz]{standalone}
\usetikzlibrary{shapes.geometric,automata}
\begin{document}
\begin{tikzpicture}[auto,>=latex]
\node[draw,minimum size=0cm,inner sep=0,regular polygon,regular polygon sides=3] at (-5,-1.3) {\kern-0.15emfoo\kern-0.15em};
\node[draw,minimum size=0cm,inner sep=0,regular polygon,regular polygon sides=3] at (-5,-1.3) {\kern-0.5emfoo\kern-0.5em};
\end{tikzpicture}
\end{document}
Best Answer
The solution is to use
shape border rotateinstead ofrotate: