[Tex/LaTex] the difference between ‘fil’ and ‘fill’

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TeX provides the commands \vfil and \vfill (and their corresponding horizontal versions \hfil and \hfill).

These commands are actually defined as:

\vskip 0cm plus 1fil
\vskip 0cm plus 1fill

where 'fil' and 'fill' (and in fact filll) are units of infinite glue with increasing orders of infinity. Here's a quote from the TeXBook (p. 71):

TeX actually recognizes several kinds
of infinity, some of which are “more
infinite” than others. You can say
both \vfil and \vfill; the second is
stronger than the first. In other
words, if no other infinite
stretchability is present, \vfil will
expand to fill the remaining space;
but if both \vfil and \vfill are
present simultaneously, the \vfill
effectively prevents \vfil from
stretching. You can think of it as if
\vfil has one mile of stretchability,
while \vfill has a trillion miles.

This much I know, at least in theory, and I also know that I can use the fil and fill versions of the spacing commands with different effects.

What I'm less clear on, is why the commands work the way they do, and what the whole concept of "infinite glue" actually means.

So can someone help to elucidate the Knuth quote a bit?

Best Answer

Let's look at the simplest case

\hbox to \hsize{<horizontal material>}

Among the <horizontal material> there will be also glue, implicit (that is, space tokens) or explicit (\hskip commands).

TeX maintains two four dimensional vectors in order to compute the glue ratio, say v for the stretching and w for the shrinking. A glue such as

\hskip 4pt plus 2pt minus 1pt

contributes 2pt to the first component of v and 1pt to the first component of w. A glue such as

\hskip 6pt plus 1fil minus 0.5fill

contributes 1 to the second component of v and 0.5 to the third component of w. At the end we'll have

v=(finite, first order infinite, second order infinite, third order infinite)

and similarly for w, where the components are the sum of all contributions. TeX also maintains the sum of the natural widths of characters, boxes and glues in the <horizontal material>.

When TeX has finished gathering the material for the \hbox, it compares the natural width to the desired box width (in our example to \hsize) and decides what to do. If the natural width is equal to the desired width, it typesets the box. Otherwise it decides that it has to stretch or shrink the glue. In the former case it looks at v and in the latter to w.

Let's look at the stretching case (the other is similar). If v is zero, there' little to do: there's no glue or the glues all cancel with each other: the box will be underfull.

Otherwise one entry in v will be different from zero; TeX will choose the rightmost non-zero component. This is the order of infinity that wins (it may be the "finite" component). The excess space to fill is then distributed proportionally among the glues that contributed that order of infinity.

Let's look at some examples

\hbox spread 3cm{A\hskip 4pt plus 2pt minus 1pt
                 B\hskip 4pt plus 1fil minus 1pt
                 C\hskip 4pt plus 2fil minus 1pt
                 D}

The box must stretch by 3cm (it's a convenient syntax for doing experiments of this kind), so we have to compute v=(2pt,3,0,0). The first-order infinity wins, so the excess space will be divided adding 1cm between B and C, and 2cm between C and D; between A and B there will be a 4pt wide space (no stretching). The result is ( denotes the resulting space)

A<4pt>B<4pt+1cm>C<4pt+2cm>D

Let's see with

\hbox spread 3cm{A\hskip 4pt plus 2pt minus 1pt
                 B\hskip 4pt plus 1fill minus 1pt
                 C\hskip 4pt plus 2fil minus 1pt
                 D}

Here v=(2pt,2,1,0), so the second-order infinity wins and the 3cm wide space will go between B and C:

A<4pt>B<4pt+3cm>C<4pt>D

Third order infinities are rarely used, but they are there for emergency cases when one has to cancel second order infinities.

The coefficient before fil(ll) should be a decimal number less than 16384 in absolute value (there must be one). The minimum non-zero value is 2^(-16)=0.000015, so saying 0.000014filll is equivalent to say 0filll (and useless, of course).

TeX has some primitives equivalent to glue specifications:

\hfil = \hskip 0pt plus 1fil minus 0pt
\hfilneg = \hskip 0pt plus -1fil minus 0pt
\hss = \hskip 0pt plus 1fil minus 1fil
\hfill = \hskip 0pt plus 1fill minus 0pt

The same algorithm is used for shrinking, but no glue will be stretched to become less than its natural width, while all glues may be used for stretching (possibly resulting in an underfull box). The same holds for vertical boxes.