[Tex/LaTex] Spanning a cell across several rows in TikZ-matrix

tikz-matrixtikz-pgf

Using the matrix-library of TikZ I am producing the following image:
current layout

\documentclass[tikz]{standalone}
\usetikzlibrary{matrix}

\begin{document}

\begin{tikzpicture}[auto, node distance=2cm,font=\small,
    every node/.style={inner sep=0pt,rectangle, minimum height=2.5em, text centered},
    comp/.style={draw,very thick,text width=2.5cm,fill=blue!10},
    crit/.style={draw,text width=2cm}]
\matrix [ampersand replacement=\&,column sep=1.5mm, row sep=3mm]
{
\node [comp] {Category\\One}; \&
\node [crit] {Attribute\\One}; \&
\node [crit] {Attribute\\Two}; \&
\\
\node [comp] {Category\\Two}; \&
\node [crit] {Attribute\\Three}; \&
\node [crit] {Attribute\\Four};
\\
\node [comp] {Category\\Three}; \&
\node [crit] {Attribute\\Five}; \&
\node [crit] {Attribute\\Six}; \&
\node [crit] {Attribute\\Seven};
\\
\node [comp] {Category\\Four}; \&
\node [crit] {Attribute\\Eight}; \&
\node [crit] {Attribute\\Nine}; \&
\node [crit] {Attribute\\Ten}; \&
\\
};
\end{tikzpicture}

\end{document}

Now, I'd like to extend this slightly to achieve such a layout (don't mind the different colours):
target layout

I just can't figure how to make one cell span several rows.
Is this possible with matrix?

Best Answer

I did a bit of cheating here, but I couldn't think a better solution.

\documentclass[tikz]{standalone}
\usetikzlibrary{matrix,calc}

\begin{document}

\begin{tikzpicture}[auto, node distance=2cm,font=\small,
    every node/.style={inner sep=0pt,rectangle, minimum height=2.5em, text centered},
    comp/.style={draw,very thick,text width=2.5cm,fill=blue!10},
    crit/.style={draw,text width=2cm}, anchor=east]
\matrix (m) [ampersand replacement=\&,column sep=1.5mm, row sep=3mm]
{
\node (A) [comp] {Category\\One}; \&
\node [crit] {Attribute\\One}; \&
\node [crit] {Attribute\\Two}; \&
\\
\node [comp] {Category\\Two}; \&
\node [crit] {Attribute\\Three}; \&
\node [crit] {Attribute\\Four};
\\
\node (C) [comp] {Category\\Three}; \&
\node [crit] {Attribute\\Five}; \&
\node [crit] {Attribute\\Six}; \&
\node [crit] {Attribute\\Seven};
\\
\node (D) [comp,text width=4cm] {Category\\Four}; \&
\node [crit] {Attribute\\Eight}; \&
\node [crit] {Attribute\\Nine}; \&
\node [crit] {Attribute\\Ten}; \&
\\
};

\draw[comp] (D.west |- A.north) coordinate (aux1) rectangle ($(C.south west) - (3mm,0mm)$) coordinate (aux2) {};
\node[anchor=center, rotate=90] (X) at ($(aux1)!.5!(aux2)$) {Master one};

\end{tikzpicture}

\end{document}

Result

Update

Ignasi noticed in a comment that the rectangle at the left does not perfectly align with the other cells, and suggests a workaround. Unfortunately, the workaround does not work, because coordinates aux1 and aux2 are calculated by tikz at the border of the lines of the cells, so taking into account the line width, and fitting library will use those coordinates as corners of the new node, at the middle of the border line. I.e. we will get the same result than in above code.

However, if we specify a negative inner sep for the fitted node to counteract the line width, we can achieve perfect alignment.

In addition, providing a text width to the rotated node allows the insertion of "line breaks" (\\) as requested by the OP.

This is the new code:

\documentclass[tikz]{standalone}
\usetikzlibrary{matrix,calc,fit}

\begin{document}

\begin{tikzpicture}[auto, node distance=2cm,font=\small,
    every node/.style={inner sep=0pt,rectangle, minimum height=2.5em, text centered},
    comp/.style={draw,very thick,text width=2.5cm,fill=blue!10},
    crit/.style={draw,text width=2cm}, anchor=east]
\matrix (m) [ampersand replacement=\&,column sep=1.5mm, row sep=3mm]
{
\node (A) [comp] {Category\\One}; \&
\node [crit] {Attribute\\One}; \&
\node [crit] {Attribute\\Two}; \&
\\
\node [comp] {Category\\Two}; \&
\node [crit] {Attribute\\Three}; \&
\node [crit] {Attribute\\Four};
\\
\node (C) [comp] {Category\\Three}; \&
\node [crit] {Attribute\\Five}; \&
\node [crit] {Attribute\\Six}; \&
\node [crit] {Attribute\\Seven};
\\
\node (D) [comp,text width=4cm] {Category\\Four}; \&
\node [crit] {Attribute\\Eight}; \&
\node [crit] {Attribute\\Nine}; \&
\node [crit] {Attribute\\Ten}; \&
\\
};

\coordinate (aux1) at (D.west |- A.north);
\coordinate (aux2) at ($(C.south west) - (3mm,0mm)$);
\node[comp, fit=(aux1)(aux2), inner sep=-.6pt] (X) {}; 
\node[text width=3cm, text centered, anchor=center, rotate=90] at (X.center) {Master\\one};

\end{tikzpicture}
\end{document}

And the new result:

New result

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[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

The source of the difficulty is that ellipses are constructed in a particular way in TikZ. They are paths that start from the x-axis and proceed counter-clockwise around their centre. The vast majority of the time, the exact parametrisation doesn't matter. You appear to have found the one situation where it does!

In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
  #2%
  \pgf@xa=-\pgf@x
  \origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother

\tikzset{
  reversed ellipse/.style={
    ellipse,
    reverse the ellipse%
  },
  reverse the ellipse/.code={
    \let\pgfpathellipse=\revpgfpathellipse
  }
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,0) {hello world};

\node[reversed ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,-2) {hello world};
\end{tikzpicture}

\end{document}

Here's the result:

rotated ellipse

(the arrow got clipped, but you can see where it lies)

[Tex/LaTex] How to define the default vertical distance between nodes

I don't really get the question so I hope this is what you wanted. If you include a full document (such that we copy paste and see the problem on our systems) things are much more easier.

Here, you can change the default setting within a scope but your block style had a node distance which was resetting every time it is issued. I've made it 2mm such that we can see the difference easier.

\documentclass[tikz]{standalone}
\usetikzlibrary{arrows,shapes.geometric,positioning}

\begin{document}
\begin{tikzpicture}[decision/.style={diamond, draw, text width=4.5em, text badly centered, node distance=3.5cm, inner sep=0pt},
                    block/.style   ={rectangle, draw, text width=6em, text centered, rounded corners, minimum height=4em, minimum height=2em},
                    cloud/.style   ={draw, ellipse, minimum height=2em},
                    line/.style    ={draw,-latex'},
                    node distance = 1cm, 
                    auto]
    \node [block] (1st) {1st};
    \node [block, right= of 1st]  (2nd1) {2nd1};
\begin{scope}[node distance=2mm and 10mm]%Here we change it for everything inside this scope
    \node [block, above= of 2nd1] (2nd2) {2nd2};
    \node [block, below= of 2nd1] (2nd3) {2nd3};
    \node [block, right= of 2nd1] (3rd1) {3rd1};
    \node [block, above= of 3rd1] (3rd2) {3rd2};
    \node [block, above= of 3rd2] (3rd3) {3rd3};
\end{scope}
    \node [block, below= of 3rd1] (3rd4) {3rd4};
    \node [block, below= of 3rd4] (3rd5) {3rd5};

    \path [line] (1st) -- (2nd1);
    \path [line] (2nd1) -- (2nd2);
    \path [line] (2nd1) -- (2nd3);
    \path [line] (2nd2) -- (3rd3);
    \path [line] (2nd1) -- (3rd1);
    \path [line] (1st) -- (2nd1);
\end{tikzpicture}
\end{document}

enter image description here

Best Answer

Update

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

[Tex/LaTex] How to define the default vertical distance between nodes

Related Question