I guess this is one way of doing it:
\documentclass[tikz,border=5]{standalone}
\usetikzlibrary{matrix}
\begin{document}
\tikzset{
entity/.code={
\tikzset{
rounded corners,
name=#1,
inner sep=2pt,
every entity/.try,
}%
\def\entityname{#1}%
},
entity anchor/.style={matrix anchor=#1},
every entity/.style={
draw,
},
every property/.style={
inner xsep=0.20cm, inner ysep=0.075cm, anchor=west, text width=1.75in
}
}
\def\property#1{\node[name=\entityname-#1, every property/.try]{\propertysplit#1;};}
\def\properties{\begingroup\catcode`\_=11\relax\processproperties}
\def\processproperties#1{\endgroup%
\gdef\propertycode{}%
\foreach \p in {#1}{%
\expandafter\expandafter\expandafter\gdef\expandafter\expandafter\expandafter\propertycode%
\expandafter\expandafter\expandafter{\expandafter\propertycode\expandafter\property\expandafter{\p}\\}%
}%
\propertycode%
}
\def\propertysplit#1:#2;{#1:\hfill#2}
\def\entitynamenode{%
\node[every entity name/.try] (\entityname-name) {\entityname};
\draw (\entityname-name.south west) -- (\entityname-name.south east);
\\[1ex]
}
\tikzset{
every entity name/.style={every property/.try, align=center}
}
\begin{tikzpicture}[every node/.style={font=\ttfamily}, node distance=0.5in]
\matrix [entity=Employee] {
\entitynamenode
\properties{
Username : varchar(255),
Password : varchar(255),
Name : varchar(255),
LastName : varchar(255)
}
};
\end{tikzpicture}
\end{document}
As is explained in How do I draw shapes inside a tikz node? pics
can be used for defining new objects. My main problem using pics is how to place where you want because they aren't nodes
and positioning them is not so easy.
Following code shows how to define EDFA
block.
EDFA/.pic={
\begin{scope}[scale=.5]
\draw (-1,0) coordinate (in) -- (-1,1) -- (1,0) coordinate (out) -- (-1,-1) -- cycle;
\node[anchor=north,inner sep=2pt] at (0,-1) {$1$};
\end{scope}
In this case, coordinate (-1,0) will act as west
anchor and 1,0
as east. Both point will have an special name for further reference. Every pic
is placed according its own origin (0,0)
. You can use Claudio's answer to Anchoring TiKZ pics for better positioning.
As your example was simple, I'd prefer to star with EDFA
and place Source
and Sink
after it.
\documentclass[]{article}
% tikz
\usepackage{tikz}
\usetikzlibrary{positioning} %relative positioning
\begin{document}
\tikzset{%
EDFA/.pic={
\begin{scope}[scale=.5]
\draw (-1,0) coordinate (in) -- (-1,1) -- (1,0) coordinate (out) -- (-1,-1) -- cycle;
\node[anchor=north,inner sep=2pt] at (0,-1) {$1$};
\end{scope}
}
}
\begin{tikzpicture}[
block/.style={draw},
]
\draw pic (edfa) {EDFA};
\node[block, left=of edfain] (source) {Source};
\node[block, right= of edfaout] (sink) {Sink};
\draw[->] (source) -- (edfain);
\draw[->] (edfaout) -- (sink);
\end{tikzpicture}
\end{document}
I understand that your components are more complex than EDFA
because for this particular case an isosceles triangle
node with a label
will do the work and it can be used as a node
and not as a pic
:
\documentclass[]{article}
% tikz
\usepackage{tikz}
\usetikzlibrary{positioning} %relative positioning
\usetikzlibrary{shapes.geometric}
\begin{document}
\begin{tikzpicture}[
block/.style={draw},
edfa/.style={isosceles triangle, minimum width=1cm,
draw, anchor=west, isosceles triangle stretches,
minimum height=1cm, label=-80:#1}
]
\node[block] (source) {Source};
\node[edfa=1, right=of source] (edfa) {};
\node[block, right= of edfa] (sink) {Sink};
\draw[->] (source) -- (edfa);
\draw[->] (edfa) -- (sink);
\end{tikzpicture}
\end{document}
Best Answer
I don't know with
pgfmath
; withexpl3
you can compile your table like this:Here's the start:
And here's the end, just to show what happens at 89 degrees:
I used five digits for comparison with the value
bc
returns for the tangent of 89 degrees: