[Tex/LaTex] LaTeX table cell with a diagonal line and 2 sub cells

tables

Possible Duplicate:
Diagonally divided table cell
Diagonal lines in table cell

I'd like to have a LaTeX table, where the top left cell marks what the headers are to the right and also mark what the descriptors are downwards.

For this I'd like to have the upper left table cell be "split" diagonally, (from top left of cell to bottom right) by drawing a line and above that line, I'd like to place the name of headings to the right, and below the headings of the descriptors downwards.

Any idea how I could do that?

Best Answer

You can use the slashbox package to do this. The following minimal example was taken directly from the examples page:

\documentclass{article}
\usepackage{slashbox}
\begin{document}

\begin{tabular}{|l||*{5}{c|}}\hline
\backslashbox{Room}{Date}
&\makebox[3em]{5/31}&\makebox[3em]{6/1}&\makebox[3em]{6/2}
&\makebox[3em]{6/3}&\makebox[3em]{6/4}\\\hline\hline
Meeting Room &&&&&\\\hline
Auditorium &&&&&\\\hline
Seminar Room &&&&&\\\hline
\end{tabular}

\end{document}

Slashbox

Related Solutions

[Tex/LaTex] Diagonal lines in table cell

Exact solution with TikZ:

\documentclass[11pt]{article}
\usepackage[T1]{fontenc}
\usepackage{array}
\usepackage{makecell}
\newcolumntype{x}[1]{>{\centering\arraybackslash}p{#1}}

\usepackage{tikz}
\newcommand\diag[4]{%
  \multicolumn{1}{p{#2}|}{\hskip-\tabcolsep
  $\vcenter{\begin{tikzpicture}[baseline=0,anchor=south west,inner sep=#1]
  \path[use as bounding box] (0,0) rectangle (#2+2\tabcolsep,\baselineskip);
  \node[minimum width={#2+2\tabcolsep},minimum height=\baselineskip+\extrarowheight] (box) {};
  \draw (box.north west) -- (box.south east);
  \node[anchor=south west] at (box.south west) {#3};
  \node[anchor=north east] at (box.north east) {#4};
 \end{tikzpicture}}$\hskip-\tabcolsep}}

\begin{document}
\setlength{\extrarowheight}{0.1cm}
\begin{tabular}{|x{0.5cm}|x{0.5cm}|x{0.5cm}|x{0.5cm}|x{0.5cm}|}\hline
&&&&20\\ \hline
&&&&30\\ \hline
&&&&45\\ \hline
15&12&18&50&\diag{.1em}{.5cm}{$a_i$}{$b_j$}\\ \hline
\end{tabular}
\end{document}

enter image description here

Also it is a reimplementation of \diaghead.

[Tex/LaTex] Tables in Latex with diagonal first row

This is a conceptual and kind of a manual solution. We first inject \tikzmarks into the column seperators and then use them to draw over the table which sits in a TikZ node.

\documentclass{article}
\usepackage{tikz,array}
\usetikzlibrary{calc}
\newcommand{\tikzmark}[1]{\tikz[remember picture,overlay]\coordinate (#1);}

\newcolumntype{T}[1]{@{\hspace{\tabcolsep}}c@{\hspace{\tabcolsep}\tikzmark{#1}}}

\begin{document}
\begin{tikzpicture}[remember picture]
\node[inner xsep=-\pgflinewidth,inner ysep=-\pgflinewidth] at (0,0) (mytable){%
\begin{tabular}{|T{a}|T{b}|c|}
\hline A&B&C\\
$\alpha$ & $\beta$ & $\theta$\\
foo &bar &Hello world \\\hline
\end{tabular}
};
\draw (mytable.north east) --++ (60:3cm);
\draw (mytable.north west) --++ (60:3cm);
\draw (mytable.north-|a) --++ (60:3cm);
\draw (mytable.north-|b) --++ (60:3cm);
\draw (mytable.north east) ++ (60:3cm) --([shift={(60:3cm)}]mytable.north west);

\node[rotate=60,anchor=west] at ($(mytable.north-|a)!0.5!(mytable.north west)$) {First Column};
\node[rotate=60,anchor=west] at ($(mytable.north-|a)!0.5!(mytable.north-|b)$) {Second Column};
\node[rotate=60,anchor=west] at ($(mytable.north-|b)!0.5!(mytable.north east)$) {Third Column};
\end{tikzpicture}
\end{document}