From what I know of beamer:
\begin{frame}<92> means \begin{frame}<beamer:92|handout:1>
similarly
\only<5> means \only<beamer:5|handout:1>
In handout mode, if overlays do not contain specification for handout mode, all slides of a frame are the same and contain all overlay elements (except \alt for which it is the alternative one, I think but I am not sure). So printing one specific slide of a frame in handout mode does not make sense, unless overlays contain a specification for handout mode.
In the extreme case where you want the overlays to be the same in beamer and handout modes, you give an overlay specification for "all" modes.
\only<all:5>
So to do what you want:
\begin{frame}<handout:92>
...
\only<all:5-97>
...
\only<all:143>
...
\end{frame}
The following code demonstrates an easier solution for what you seem to be willing to do.
\documentclass[handout]{beamer}
\usepackage{tikz}
\begin{document}
\begin{frame}
\foreach \n in {1,...,10} {
\pgfmathtruncatemacro{\oneifnisfive}{\n==5}
\only<\n| handout:\oneifnisfive>{Slide \n\par}
}
\end{frame}
\begin{frame}<handout:5>
\foreach \n in {1,...,10} {
\only<all:\n>{Slide \n\par}
}
\end{frame}
\end{document}
Best Answer
Something like this! Here only
tikz
package is used to assure that the return button is located at the same place on the explanation page. Every beamer page that has links should have a label (main, here, there in this example), then use the following command at proper locations.Code