[Tex/LaTex] How to draw these empty open dots

tikz-pgf

\documentclass[border=2mm,tikz]{standalone}

\usepackage{textcomp}
\usepackage{tikz}

\begin{document}

\begin{tikzpicture}[scale=0.3]
    \draw
        (1, 2)
        node {\textopenbullet}
        node[below] {$(1, 2)$}
        rectangle (8, 4)
        rectangle (6, 11)
        rectangle (13, 13)
        node {\textopenbullet}
        node[above] {$(13, 13)$};
\end{tikzpicture}


\end{document}

How do I make sure the node (1,2) is just an empty white circle?

Thanks!

enter image description here

Best Answer

I like to avoid fill=white. While the rectangle path operator does not “care” for nodes, the orthogonal path operators -| and -| do. With a to path, a rectangle path consisting of two -| can be easily re-created. (As the rectangle path operator does not work quite good with nodes along a path either, I left out \tikztonodes in the definition of the to path but it can get added easily, if needed.)

If you add outer sep=0pt to the definition of the circ style, the lines get drawn to the middle of the circular line and you can avoid easily the (hardly noticeable) connection problems as highlighted in Better fitting line to node in TiKZ. Another solution would be to use line cap=round or line cap=rect (line cap=butt is the default).

Code

\documentclass[border=2mm,tikz]{standalone}
\usepackage{tikz}
\tikzset{rect/.style={to path={-| (\tikztotarget) -| (\tikztostart) (\tikztotarget)}}}
\begin{document}
\begin{tikzpicture}[scale=0.3,
  circ/.style={shape=circle, inner sep=1pt, draw, node contents=}]
    \draw node (c1) at (1, 2) [circ, label=below:{$(1,2)$}]
          node (c2) at (13,13)[circ, label=above:{$(13,13)$}]
     (c1) to[rect] (8,4) to[rect] (6,11) to[rect] (c2);
\end{tikzpicture}
\end{document}
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