What's a "fancy" f I can use to denote a Fourier transform?
(I mean something fancier than what \mathcal{F} provides.)
[Tex/LaTex] Fourier Transform (super-fancy) “f”
math-operators
Related Solutions
The calligraphic letters are in the OMS encoding
\documentclass{article}
\usepackage{calrsfs}
\DeclareMathAlphabet{\pazocal}{OMS}{zplm}{m}{n}
\newcommand{\La}{\mathcal{L}}
\newcommand{\Lb}{\pazocal{L}}
\begin{document}
$\La\Lb$
\end{document}
The example defines \eexists and \fforall with the additional lines as requested in the question.
\eexists: The symbol\eexistsis composed of\existsand the vertical line|to get a line with a matching line thickness. The vertical line is scaled to the right height. This vertical scaling does not change the horizontal line width. Finally the line is moved to the right position.\fforall: The trick with the vertical line cannot be uses, because the angle is not known exactly. Also the angle depends on the font size. The angle can be estimated from the width and height of the symbol. For this symbolTikZis used and the line width is guessed from the width of\forall.
Update:
- Decreased distance between the two lines.
- I have removed the case for
\scriptscriptstyle, because the symbols have larger side bearings that would need to be compensated. But probably the symbols are not needed at such sizes anyway. - Of course, the "magic numbers" depend on the used font. A different font might need different settings.
Example file:
\documentclass{article}
\usepackage{graphicx}
\usepackage{tikz}
\makeatletter
\newcommand*{\eexists}{%
{\mathpalette\eexistsAux{}}%
}
\newcommand*{\eexistsAux}[2]{%
\exists
\sbox0{$\m@th#1\exists$}%
\sbox2{\raisebox{\depth}{$\m@th#1|$}}%
\kern-.5\wd2 %
\resizebox{\width}{\ht0}{\copy2}%
\kern-.25\wd2 %
}
\newcommand*{\fforall}{%
{\mathpalette\fforallAux{}}%
}
\newcommand*{\fforallAuxx}[1]{%
\sbox0{$\m@th#1\forall$}%
\sbox2{%
\rlap{%
\raisebox{\depth}{$\m@th#1\backslash$}%
}%
\kern\ht0 %
}%
\sbox2{\resizebox{\ht2}{\height}{\copy2}}%
\sbox2{\resizebox{!}{\ht0}{\copy2}}%
\wd2=0pt %
\copy2
\forall
}
\newsavebox\forallBox
\newdimen\forallLineWidth
\newdimen\forallSep
\newcommand*{\fforallAux}[1]{%
\sbox\forallBox{$\m@th#1\forall$}%
\setlength{\forallLineWidth}{.06\wd\forallBox}%
\setlength{\forallSep}{.09\wd\forallBox}%
\tikz[
inner sep=0pt,
line cap=round,
line width=\forallLineWidth,
]
\draw
(0,0) node (A) {\copy\forallBox}
(A.south) ++(-\forallSep-\forallLineWidth,.4\forallLineWidth)
coordinate (A1)
(A.north west) ++(-\forallSep,-\forallLineWidth)
coordinate (A2)
(A1) -- (A2)
;%
}
\makeatother
\begin{document}
\setlength{\fboxsep}{0pt}
\renewcommand*{\arraystretch}{1.5}
\begin{tabular}{cc}
\fbox{$\forall$} & \fbox{$\exists$}\\
\fbox{$\fforall$} & \fbox{$\eexists$}\\
$\forall^\forall$ & $\exists^\exists$ \\
$\fforall^\fforall$ & $\eexists^\eexists$\\
\end{tabular}
\end{document}
Best Answer
(Added as answer by request of the OP)
One way to get a fancier
Fthan\mathcalprovides is to use the\mathscrcommand provided by themathrsfspackage:gives
To compare other fancy
Fs:\mathfrak{F}from theamssymbpackage gives\mathcalgives