I get 6 errors when I use the code below – all 6 of them occur on the line that contains only \end{align*}
. The code between the \begin{align*}
and \end{align*}
works as a displayed equation.
\begin{align*}
p_{\text{undetect}}
&=\sum_{i=0}^{n} {{A_i}{p^i}{(1-p)^{n-i}}} \\
&={{(1-p)^n}{\sum_{i=0}^{n} {{A_i}{\left({\frac{p}{1-p}}\right)}^i}} \\
&={(1-p)^n}\left[\left({\sum_{i=0}^{n} {{A_i}{{\left({\frac{p}{1-p}}\right)}^i}}}\right)-{A_{0}}\right] \\
&={(1-p)^n}}\left[A\left(\frac{p}{1-p}\right)-1\right]
\end{align*}
Four of the error messages are either Missing { inserted
or Missing } inserted
. The other two error messages are Missing \endgroup
and Misplaced \omit
.
Best Answer
Your use of the grouping chars
{
and}
is misleading. First, here is the correct way of writing your formula:The rule for using the grouping chars here is quite straight forward (as in most other cases): You need to group arguments of macros as in
\frac{...}{...}
, which apparently takes two arguments, and you need to group the content that is parsed by the special characters^
and_
(e.g.A_ijk
differs dramatically fromA_{ijk}
and in contrast to what one possibly could think{A_ijk}
is not analogous to latter one but to the first example). Any other group is simply superflous. However,A_i
andA_{i}
are analogous. Even though in the second case the group isn't mandatory, most would recommand to use it to have a uniform input.