How to draw a horizonal line across a row (over the entries) in an array?
[Tex/LaTex] Draw a horizonal line over the entries of a row in an array
arrays
Related Solutions
Here is an adaption of Draw a line through one column of a matrix:
Notes:
- This does require two runs. First one to determine the locations, and the second to do the drawing.
- Another option is to use the
tikzmarkpackage, but for this particular case it is simpler to not use that package: The custom defined\MyTikzmarkprovides anchor points.northand.southwhich are automatically centered vertically. Similarly.eastand.westare centered vertically. In thetikzmarkpackage version the lines were extended viashorten >=andshorten <=and shifted usingyshiftto provide similar results.
Code: Without tikzmark package.
\documentclass{article}
\usepackage{amsmath}
\usepackage{tikz}
\newcommand{\MyTikzmark}[2]{%
\tikz[overlay,remember picture,baseline] \node [anchor=base] (#1) {$#2$};%
}
\newcommand{\DrawVLine}[3][]{%
\begin{tikzpicture}[overlay,remember picture]
\draw[shorten <=0.3ex, #1] (#2.north) -- (#3.south);
\end{tikzpicture}
}
\newcommand{\DrawHLine}[3][]{%
\begin{tikzpicture}[overlay,remember picture]
\draw[shorten <=0.2em, #1] (#2.west) -- (#3.east);
\end{tikzpicture}
}
\begin{document}
\[
\begin{bmatrix}
\MyTikzmark{leftA}{15} & 0 & \MyTikzmark{topB}{0} & \MyTikzmark{rightA}{0} \\
0 & 50 & 20 & 25 \\
35 & 5 & 0 & 10 \\
\MyTikzmark{bottomA}{0} & 65 & \MyTikzmark{bottomB}{50} & 65
\end{bmatrix}
\]
\DrawVLine[red, thick, opacity=0.5]{leftA}{bottomA}
\DrawVLine[orange, thick, opacity=0.5]{topB}{bottomB}
\DrawHLine[blue, thick, opacity=0.5]{leftA}{rightA}
\end{document}
Code: With tikzmark package.
\documentclass{article}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{calc,tikzmark}
\newcommand{\MyTikzmark}[2]{%
\tikz[remember picture,baseline]
\node [anchor=base, inner sep=0pt, outer sep=0pt]
{\tikzmark{#1 LEFT}$#2$\tikzmark{#1 RIGHT}};%
}
\newcommand{\DrawVLine}[3][]{%
\begin{tikzpicture}[overlay,remember picture]
\draw[shorten <=-1.7ex, shorten >=-0.3ex, #1]
($(pic cs:#2 LEFT)!0.5!(pic cs:#2 RIGHT)$) --
($(pic cs:#3 LEFT)!0.5!(pic cs:#3 RIGHT)$);
\end{tikzpicture}
}
\newcommand{\DrawHLine}[3][]{%
\begin{tikzpicture}[overlay,remember picture]
\draw[shorten <=-0.2em, shorten >=-0.3em, yshift=0.7ex, #1]
(pic cs:#2 LEFT) -- (pic cs:#3 RIGHT);
\end{tikzpicture}
}
\begin{document}
\[
\begin{bmatrix}
\MyTikzmark{leftA}{15} & 0 & \MyTikzmark{topB}{0} & \MyTikzmark{rightA}{0} \\
0 & 50 & 20 & 25 \\
35 & 5 & 0 & 10 \\
\MyTikzmark{bottomA}{0} & 65 & \MyTikzmark{bottomB}{50} & 65
\end{bmatrix}
\]
\DrawVLine[red, thick, opacity=0.5]{leftA}{bottomA}
\DrawVLine[orange,thick, opacity=0.5]{topB}{bottomB}
\DrawHLine[blue, thick, opacity=0.5]{leftA}{rightA}
\end{document}
With a simple array environment:
\documentclass[12pt]{article}
\usepackage{array,amsmath}
\begin{document}
$\arraycolsep=2pt
\begin{array}{ | *7c | *8c }\cline{1-7}
\rule{0pt}{3ex}% more vertical space for 1st line
c^{(1)} & \geq & c^{(2)} & \geq & \cdots & \geq & c^{(j)} & \geq & \cdots & \geq &
c^{((N-1)K+1)} & \geq & \cdots & \geq & c^{(NK)}\\
\downarrow & & \downarrow & & & & \downarrow & & & & \downarrow & & & &
\downarrow \\
\gamma^{(1)} & & \gamma^{(2)} & & \cdots & & \gamma^{(j)} & & \cdots & &
\gamma^{((N-1)K+1)}& &\cdots & & \gamma^{(NK)}\\\cline{1-7}
\end{array}
$
\end{document}
Best Answer
The following macro
\overtablineputs a line in the middle of the previous table row assuming the row is not larger than\@arstrut(\strutfor tables that also include the setting of\arraystretch).