captionshorizontal alignment
There are multiple questions already answered for centering an entire caption, but my problem is that I wish to just \centerline or \begin{center} ... \end{center} just one line in a multi-line caption.
For example (I am using the \ce package for chemistry) if I were to write the following:
\caption{In the presence of A and B, C will be generated:
\centerline{ \ce{A + B -> C}.}
}
Will just error out on me.
like this?
\documentclass[12pt]{book}
\usepackage{pgfplots}
\pgfplotsset{compat = newest}
\usepackage{pgfplotstable}
\usepackage{booktabs, makecell}
\newcolumntype{C}[1]{>{\centering\arraybackslash}p{#1}} % <--- for centering
%-------------------------------- show page layout, only for test
\usepackage{showframe}
\renewcommand\ShowFrameLinethickness{0.15pt}
\renewcommand*\ShowFrameColor{\color{red}}
%---------------------------------------------------------------%
\begin{document}
\begin{table}%[htpb]
\centering
\setlength\extrarowheight{2pt}
\pgfplotstabletypeset[
col sep=&,
row sep=\\,
string type,
columns = {Divisor, Rule, Example},
columns/Divisor/.style={column name={\textbf{Divisor}},
column type={@{}C{.2\dimexpr\textwidth-4\tabcolsep}}} , % <--- correct calculation of column width
columns/Rule/.style={column name={\textbf{Rule}},
column type={C{.5\dimexpr\textwidth-4\tabcolsep} }} , % <---
columns/Example/.style={column name={\textbf{Example}},
column type={C{.3\dimexpr\textwidth-4\tabcolsep}@{} }} , % <---
every head row/.style=
{before row=\toprule\toprule, after row=\bottomrule},
every last row/.style=
{after row=\bottomrule\bottomrule},
]
{
Divisor & Rule & Example \\
2 & If the last digit is 0, 2, 4, 6 or 8 & $C'mon\ Man!$ \\ \hline
3 & If sum of digits is divisible by 3 & $ 921 \rightarrow \frac{9 + 2 + 1}{3} = 4 $ \\ \hline
4 & If number formed by last two digits is divisible by 4 & $ 524 \rightarrow\ \frac{24}{4} = 6 $ \\ \hline
5 & If last digit is 0 or 5 & $C'mon\ Man!$ \\ \hline
6 & If it is divisible by 2 AND divisible by 3 & $\frac{468}{2} = 234,\ \frac{468}{3} = 156$ \\ \hline
6 & If it is divisible by 2 AND divisible by 3 & \Gape[6pt]{\makecell{$\frac{468}{2} = 234$ \\ {} \\ $\frac{468}{3} = 156$}} \\ \hline
7 & No rule exists & {} \\ \hline
8 & If number formed by last three digits is divisible by 8 & $ 24,296 \rightarrow \frac{296}{8} = 37 $ \\ \hline
9 & If sum of digits is divisible by 9 & $549 \rightarrow \frac{5+4+9}{9} = 2$ \\
}
\caption{Divisibility rules for the integers less than 10.}
\end{table}
\end{document}
edit:
C (you can choose another letter for its name). it is derived from p{...} with added option \centering. since it interfere with \\ on the end of rows, is added \arraybackslash which restore original meaning of \\ .\dimexpr defined in latex kernel. to have table width equal to \textwidth you should:
\tabcolsep. table span six this lengths (each column has two, one on begin column, one on its end), but two of them (the first and the last one) are eaten by @{} on beginning and end of column specification. therefore the width, which is shared between columns is \textwidth - 4\tabcolsepaddendum:
so far i didn't bother with table content. now i inspect it ... so below are some suggestion how to improve it:
p{...} column type use m{..} type (provided by package array).m{...} type is not compatible with makecell package, it should be removed\hline use \midruleamsmath package for aligned environmentwith this changes your table become:
\documentclass[12pt]{book}
\usepackage{pgfplots}
\pgfplotsset{compat = newest}
\usepackage{pgfplotstable}
\usepackage{booktabs}
\newcolumntype{C}[1]{>{\centering\arraybackslash}m{#1}}
\usepackage{amsmath}
%-------------------------------- show page layout, only for test
\usepackage{showframe}
\renewcommand\ShowFrameLinethickness{0.15pt}
\renewcommand*\ShowFrameColor{\color{red}}
%---------------------------------------------------------------%
\begin{document}
\begin{table}%[htpb]
\centering
\pgfplotstabletypeset[
col sep=&,
row sep=\\,
string type,
columns = {Divisor, Rule, Example},
columns/Divisor/.style={column name={\textbf{Divisor}},
column type={@{}C{.15\dimexpr\textwidth-4\tabcolsep}}} ,
columns/Rule/.style={column name={\textbf{Rule}},
column type={C{.5\dimexpr\textwidth-4\tabcolsep} }} ,
columns/Example/.style={column name={\textbf{Example}},
column type={>{$\displaystyle}%
C{.35\dimexpr\textwidth-4\tabcolsep}<{$}
@{} }} ,
every head row/.style=
{before row=\toprule, after row=\midrule},
every last row/.style=
{after row=\bottomrule},
]
{
Divisor & Rule & Example \\
2 & If the last digit is 0, 2, 4, 6 or 8
& \textit{C'mon Man!} \\
\midrule
3 & If sum of digits is divisible by 3
& 921 \rightarrow \frac{9 + 2 + 1}{3} = 4 \\
\midrule
4 & If number formed by last two digits is divisible by 4
& 524 \rightarrow\ \frac{24}{4} = 6 \\
\midrule
5 & If last digit is 0 or 5
& \textit{C'mon Man!} \\
\midrule
6 & If it is divisible by 2 AND divisible by 3
& \frac{468}{2} = 234,\ \frac{468}{3} = 156 \\
\midrule
6 & If it is divisible by 3 AND divisible by 2
& {\begin{aligned}\frac{468}{3}&=156\\
\frac{468}{2}&=234
\end{aligned}} \\
\midrule
7 & No rule exists
& \\
\midrule
8 & If number formed by last three digits is divisible by 8
& 24,296 \rightarrow \frac{296}{8} = 37 \\
\midrule
9 & If sum of digits is divisible by 9
& 549 \rightarrow \frac{5+4+9}{9} = 2 \\
}
\caption{Divisibility rules for the integers less than 10.}
\end{table}
\end{document}
Best Answer
This should do the job:
The most convenient way how to center an equation is to use the
equationmore, which is done by\[..\]. However, you can't bring that to the list of floats, because that causes errors, well, you don't want the equation on display in the list of floats, do you? So the short caption is the solution.