# [Tex/LaTex] About big parenthesis larger than Bigg

amsmathdelimitersmultlinescaling

Do any one know how to type a very big parenthesis in LaTeX. Since the formula is very big, I used multline environment, in one line, there are many pair of parenthesis by using \left and \right which make them already very big. Between lines, I need some parenthesis bigger than the one given by \Bigg. My intention is to show the following big formula in multline environment:

$$\frac{ e^{-\frac{t \lambda +4}{4 \lambda \nu }} \left( e^{\frac{t}{4 \nu }} \left( 4 \sqrt{\pi } \sqrt{\nu }+1 \right) \nu \Phi \left( \frac{t-\frac{2}{\lambda }}{\sqrt{2} \sqrt{t \nu }} \right) \lambda^3 -e^{\frac{t \lambda +8}{4 \lambda \nu }} \left( 4 \sqrt{\pi } \sqrt{\nu }-1 \right) \nu \left( \Phi \left( \frac{t+\frac{2}{\lambda }}{\sqrt{2} \sqrt{t \nu }} \right) -1 \right) \lambda^3 +e^{\frac{1}{\lambda \nu }} \left( 4 \sqrt{\pi } \lambda^3 \nu^{3/2} \left( 2 \Phi \left( \frac{1}{\sqrt{2} \lambda \sqrt{t \nu }} \right) -1 \right) -e^{\frac{t}{4 \nu }} \left( \left( \lambda \left( 4 \sqrt{\pi } \sqrt{\nu }-1 \right) \nu +2 \right) \lambda^2+2 (\lambda \nu -2) \Phi \left( \frac{\sqrt{\frac{t}{\nu }}}{\sqrt{2}} \right) \lambda^2-2 \right) \right) \right) }{4 \lambda }$$


The ams parenthesis of specific size are typeset by using \left and \right and putting in an invisible "thing" of a certain height to ensure that they are big enough. Mimicking that, you could do: \left(\rule{0cm}{2cm}\right. to get a left parenthesis of 2cm height. Note that the AMS command also adds a little horizontal space which you might need to put in as well. If you do this often, you could easily define new sizes:

\makeatletter
\newcommand{\vast}{\bBigg@{4}}
\newcommand{\Vast}{\bBigg@{5}}
\makeatother


$\Vast( \frac{\prod_0^\infty k}{\sum_0^\infty n} \Vast)$

(Note I've assumed that you're using amsmath since you tag it with amsmath and the commands \big and so forth are ones that amsmath produces. If you're using a different package to get these commands, then this solution won't work.)