[Physics] Newton’s 3rd Law and a bouncing ball

collisionforcesnewtonian-mechanics

just want to clear something up.

Take a ball that's been dropped to the ground. Gravity acts and this ball as it has mass and then the ball now moves to the ground with a constant force of say ($$X$$).

Now when the ball makes contact with the ground, Newtons 3'rd Law takes effect (no air resistance):

If object A (the ball) exerts a force on object B (the floor), then object B will exert an equal force on object A in the opposite direction. (Action has equal opposite reaction).

Now here's where I get confused.

If the ball (which has a constant force when it hits the ground ($$X$$)) experiences the same constant force in the opposite direction ($$-X$$, minus indicating opposite direction), then the total force acting on the ball should be net ZERO ( $$X + (-X) = 0$$).

So there are no net forces acting on the ball, so why does it BOUNCE BACK? What am I missing?

Shouldn't the ball just stay on the ground? Bouncing back means a force greater than (-X) was applied to the ball giving it upward motion. Where did it come from?

First, $$X=mg$$, force of Earth's mass pulling on the ball. Second, Newton's 3rd Law (N3L) is always in effect; the ball is pulling on the Earth while the ball falls.
Objects do not have or possess or carry force. A force results from an interaction of two things (ball/Earth or ball/floor) and acts on an object. While the interaction of the ball with Earth manifests in a constant force on the ball, that force has very little to do with the force magnitude between the floor and ball, beyond the velocity which results from the acceleration of $$g$$. I believe that is the big mistake you are making.