# [Physics] Fields and Newton’s Third Law

conservation-lawsfield-theorymomentumnewtonian-mechanics

I'm studying basic physics. I'm using the text available at http://www.anselm.edu/internet/physics/cbphysics/downloadsI.html. It develops the universal law of gravitation by postulating the existence of a vector at each point of the form

$$g_P = \sum G\frac{m_i}{|r|_i^3}r_i,$$

Where $m_i$ and $r_i$ are the mass of and separation vector from $P$ for all particles that aren't at the point $P$.

It examines the effect of one particle on another. If the separation vector is $r$ then from the above equation, we see that

$$g = G\frac{m_1}{|r|^3}r$$

and that when a particle of mass $m_2$ is placed at the given point, the force will be

$$F = G\frac{m_1m_2}{|r|^3}r$$

The authors then go on to claim that we can either repeat the development to see the effect of the second particle on the first one or apply Newton's third law.

How does Newton's third law apply through a field? If it's the field exerting the force, then Newton's third law would require a force on the field and not the object "generating" the field, correct?

In Newtonian physics, the field is not really something physical that has an independent existence. Particularly in Newtonian gravity, the gravitational force is really action at a distance with nothing mediating the force in between. The field $g$ defined here is simply for mathematical convenience and is not the usual field that you talk about in a fully relativistic classical field theory.
So as long as you're not doing any relativistic calculations and asking questions like "Does the force act instantaneously? In what frame?", it's perfectly fine to just treat the particles as obeying the Third Law, with equal and opposite forces between them that act at a distance, and use the field $g$ only as a convenience.
Summary: Don't take the "field" $g$ in a physical sense.