This is inspired by Griffiths QM section 2.2, on the infinite square well, which is about how far I've gotten (so, sorry if this is addressed later in the book).

For any given starting wavefunction, you can express it as a sum over the solutions of the time-independent Schrödinger equation. The coefficients in the sum are constant in time, therefore the expectation value of energy is constant in time. The chapter says "this is a manifestation of conservation of energy in quantum mechanics." Ok.

Now in problem 2.5, we have a wavefunction that is an even mixture of the first two stationary states. Part D has us compute the expectation value of momentum, and the solution is sinusoidal in time. So momentum is *not* conserved.

How can momentum be not conserved? Why is energy conserved but not momentum?

## Best Answer

This subtlety is related to the fact that the momentum operator $\hat{P}$ (unlike the Hamiltonian $\hat{H}=\frac{\hat{P}^2}{2m}$) has

noeigenfunctions compatible with the Dirichlet boundary conditions, and $\hat{P}$ isnota self-adjoint operator. This is essentially Example 4 in F. Gieres,Mathematical surprises and Dirac’s formalism in quantum mechanics,arXiv:quant-ph/9907069, see p. 6, 39, 44-45. In particular, we cannot choose a common set of eigenfunctions for $\hat{P}$ and $\hat{H}$. See also e.g. this related Phys.SE post and links therein.