# [Physics] Calculating lens focal point and size for head mounted display

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I am trying to make a single-eye head mounted display.
It will be a prototype for displaying information while the person is doing other work. The important part is that the virtual image of the screen is around 1 meter away from the wearer so he will not have to adjust his focus much while working with his hands.

However I cant figure out the parameters of my lens. I have made a graphic to explain the situation:

I want to get my fixed screen size to cover all of the FOV, F,B and possibly C(adjustable) can be derived.

• Is it possible to make a function out of this using the lens formula?
• My field does not have to be perfectly flat, do i still have to worry about weird optical effect just using a biconvex lens?

Any tips on how to get my values are greatly appreciated.

I have a better idea. If you have the convex lens of focal length $C$, then the image will be at $\infty$ and your eye can see it easily. In this case the magnification will be $\frac{f_{eye}}{f_L}$. Usually the eye focal length is taken as 55 mm and the lens you will need is ~10 mm then the magnification of 5 will be there and one can see the small images clearly. You may also want to make them as reading glasses (top part with 0 power and bottom part with the high power convex lens).