MATLAB: While loop doesn’t produce correct result

while loop

sum = 0;
n = 0;
C = (2/(pi*(1-4*n^2)))^2;
while sum < (1/2)*0.99
    n = n+1;
    sum = sum + C;
end
disp(['number of terms:',num2str(n),'sum',num2str(sum)])

These are my codes. I want matlab to keep calculating until sum is greater than 99% of a half. However it stops at the first calculation and the result is clearly wrong. Any help would be greatly appreciated! Thanks!

Best Answer

You have not placed the line "C = (2/(pi*(1-4*n^2)))^2;" inside the 'while' loop where it could be updated with changing values of 'n', so 'C' stays constant. That will produce erroneous computation for you.

Related Solutions

MATLAB: How Do I to Use a While Loop to Eventually Get to a Specific Number

There is no condition for S. Every time, it keeps operating the while loop. Change the code to the following:

while true
  n=input('please input a value for n: ');
  b=1./(n.^2);
  S=sum(b);
  if (.999*(pi^(2)/6))<=S && S<=(1.001*(pi^(2)/6))
      fprintf('the sum for that value of n is %.5f\nCongrats! the sum is close enough to pi^2/6\n',S)
      break;
  else
      fprintf('the sum for that value of n is %.5f\n Please input a higher value for n.',S)
  end
end

MATLAB: Counting how many times a loop loops.

Check the code below.

% Input Varibles
  g = input('guess how many times');
% Calculate Running Sum.
loopcnt = 0;
sum = 0;
    while(sum <=21)
        n = randi ([1, 11]);
        sum = sum + n;
        loopcnt = loopcnt + 1;
    end
        disp (sum);
        disp(['number of loops: ' num2str(loopcnt)]);

Best Answer

Related Solutions

MATLAB: How Do I to Use a While Loop to Eventually Get to a Specific Number

MATLAB: Counting how many times a loop loops.

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