MATLAB: What does exitflag =2 mean for fsolve

exitflagfsolveMATLAB

I just completed and ran a fsolve loop that gave me some results with each iteration with exitflag=2
Equation solved, fsolve stalled.
fsolve stopped because the relative size of the current step is less than the
default value of the step size tolerance squared and the vector of function values
is near zero as measured by the default value of the function tolerance.
<stopping criteria details>
xopt =   1.0e+03 *
      4.4075    0.2890
Fval =     1.0e-06 *
     -0.2928
      0.0000
  exitflag =
       2
What is the significance from the solution point of view. Any suggestions?

Best Answer

From the documentation:
  • Change in x was smaller than the specified tolerance.
That essentially means that the solver stopped because it had reached an acceptable solution as specified in its options structure.
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