MATLAB: Solve non-linear equation with 2 unknowns and lb/ub constraints

optimization

Hello, I'm trying to maximize an objective function with 2 unknown variables subject to lower/upper bound constraints on the unknowns. The objective function is:
 function F = v_optimal2(v)
%br: function has two optimal speed params
F = (13597150/(1+.000273)^((2781.4+6278.5)/(24*v(1))- (34993*(2781.4+6278.5)/(24*v(1))+ ...
600*55*((v(1)/16)^3)*(2781.4+6278.5)/24*v(1))/(1+.000273)^((2781.4)/24*v(1)- 34993*(2781.4+6278.5)/(24*v(2))+ ...
600*55*((v(1)/v(2))^3)*(2781.4+6278.5)/24*v(2))));
end
To solve, I run:
 x0 = [13.5; 8]; %Make a starting guess at the solution
 [x,fval] = fminimax(@v_optimal2,x0,[],[],[],[],8,16);  %Call solver
>> solveOptimalSpeed
Local minimum possible. Constraints satisfied.
fminimax stopped because the size of the current search direction is less than
twice the default value of the step size tolerance and constraints are 
satisfied to within the default value of the constraint tolerance.
<stopping criteria details> 
Optimization stopped because the norm of the current search direction, 0.000000e+00,
is less than 2*options.TolX = 1.000000e-06, and the maximum constraint 
violation, 0.000000e+00, is less than options.TolCon = 1.000000e-06.
Optimization Metric                                               Options
norm(search direction) =   0.00e+00                        TolX =   1e-06 (default)
max(constraint violation)  =   0.00e+00                  TolCon =   1e-06 (default)
So my questions are:
1. Before I get really into depth on the stopping criteria, is this the correct Matlab function to use?
2. If minimax is okay, why isn't it solving and how do I get the max instead of min (doing -@voptimal2 did not work)

Best Answer

FMINIMAX solves a minimax objective; you have a regular maximum objective and thus should be using FMINCON with the negative output of the objective function. Also, you will need LB/UB for as many variables as you have. Since v is a two element vector, you will want LB/UB to be 1x2 vectors.
Related Question