By the help document of Matlab, the example of fsolve is:
function F = root2d(x)F(1) = exp(-exp(-(x(1)+x(2)))) - x(2)*(1+x(1)^2);F(2) = x(1)*cos(x(2)) + x(2)*sin(x(1)) - 0.5;
fun = @root2d;x0 = [0,0];x = fsolve(fun,x0)
But now outer function transfer a anonymous function of fun, like:
fun = @(x,y) [x+y^2-5, 6*x^2+13*y-5]
Start value x0 = [1, 1]
How do I fit fsolve input format?
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