MATLAB: Question about translating hexadecimal character cell

cellcell arraysdecimal matrixhexadecimal

Hello, thanks for reading this,
I have a n*5 cell of character elements that represent hexadecimal numbers. I want to take this and convert it to decimal matrix.
What I do is search through a text file, and with the lines:
   while (isempty(strfind(tline,faceMatrixEnd)) )
      vVolumeFaceMx(volumeCounter,:) = textscan(tline, '%s %s %s %s %s', 'delimiter', ' ');
      tline = fgetl(fid_source);
      volumeCounter = volumeCounter+1;
   end
I create a cell with n*5 columns, each cell element containing a string.
For instance, I can translate one element into a decimal value using:
   sscanf(my_matrix{1,1}{1,1}, '%x')
but if I wanted to do this for my entire cell, what I would do right now is use loops, which would take a while.
Is there an faster and easier way to do this?

Best Answer

I bypassed this problem by using a different command to read the text file.
using the code:
      vVolumeFaceMx(:,volumeCounter) = sscanf(tline, '%x %x %x %x %x');
      tline = fgetl(fid_source);
      volumeCounter = volumeCounter+1;
allowed me to read it into a hexadecimal format to begin with.
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