MATLAB: Am I not getting the correct Laplace Transform of a Heaviside step function assumeheavisidelaplaceSymbolic Math Toolbox Best Answer This is the expected behavior because the Laplace Transform of the Heaviside step function depends on whether a > 0 or a < 0.For a > 0: laplace(heaviside(t-a)) = exp(-a*s)/sFor a < 0: laplace(heaviside(t-a)) = 1/sIn order to get the desired output, specify the assumption for the variable "a":>> syms a t >> assume(a > 0); >> laplace(heaviside(t-a)) ans = exp(-a*s)/s Related SolutionsMATLAB: How to change the axis limit when I have 2 axes in the figure You can use the "yyaxis" and "ylim" commands to set the y-limit for both axes:>> figure>> yyaxis left>> plot(1:10);>> yyaxis right>> plot(2:2:20);>>>> f = gcf;>> yyaxis left>> ylim(f.Children, [0 5]);>> yyaxis right>> ylim(f.Children, [5 10]); MATLAB: Does vpasolve give answers that ignore the assumptions According to the documentation, "vpasolve" ignores any assumptions on your variables:https://www.mathworks.com/help/symbolic/vpasolve.html#bt51ety-1_1However, you can instead specify the ranges you want to find solutions in as inputs to "vpasolve" in the following way:>> vpasolve(<eqn>, [a b], [0 1;0 2]) % The matrix at the end sets the bounds for each of the variables. Related QuestionIs implementing the “fft” formula in documentation giving me opposite sign for imaginary partHow to create a pictogram in MATLABHow to use custom date labels for the x-axis in MATLAB plotsWhat can I do if I am on a trial and getting license number 0 from the ver command
Best Answer
This is the expected behavior because the Laplace Transform of the Heaviside step function depends on whether a > 0 or a < 0.
For a > 0: laplace(heaviside(t-a)) = exp(-a*s)/s
For a < 0: laplace(heaviside(t-a)) = 1/s
In order to get the desired output, specify the assumption for the variable "a":