MATLAB: Multiple answers into single array

arrayfor loopmatricemax

Below is my current workspace in MATLAB. 
theta = linspace(0,2*pi);
for a = [10:0.1:14]
    c = 30-a;
    bt = -a.*sin(theta)+((a.^2*sin(theta).*cos(theta))/sqrt(c.^2-a.^2*sin(theta).^2));
    M = [max(bt)]
end
When I run this file it gives me the maximum value of 41 arrays. The answer shows like this:
M =
13.5983
M =
13.6983
M =
13.7983
M =
13.8983
M =
13.9982
I am wondering is there a way I can make my answer into a single array which I can then plot against a(10:14)?
I wish for it to look something like this:
M =
13.5983 13.6983 13.7983 13.8983 13.9982
OR
M =
13.5983
13.6983
13.7983
13.8983
13.9982
Any help would be great

Best Answer

This is definitely possible! Since you aren't using integers for indexing, there are a couple of ways to do it:
theta = linspace(0,2*pi);
M = []; % Create empty M

for a = [10:0.1:14]
    c = 30-a;
    bt = -a.*sin(theta)+((a.^2*sin(theta).*cos(theta))/sqrt(c.^2-a.^2*sin(theta).^2));
    M = [M max(bt)]; % Add max(bt) to the end of M every loop

end
% Also
theta = linspace(0,2*pi);
count = 1; % Create empty M
for a = [10:0.1:14]
    c = 30-a;
    bt = -a.*sin(theta)+((a.^2*sin(theta).*cos(theta))/sqrt(c.^2-a.^2*sin(theta).^2));
    M(count) = max(bt);
    count = count+1;
end
% Or
theta = linspace(0,2*pi);
area_of_interest = 10:0.1:14;
count = length(area_of_interest);
for k = 1:count
    a = area_of_interest(k)
    c = 30-a;
    bt = -a.*sin(theta)+((a.^2*sin(theta).*cos(theta))/sqrt(c.^2-a.^2*sin(theta).^2));
    M(k) = max(bt); % Add max(bt) to the end of M every loop
end
For plotting against a(10:14), I want to check about what you mean.
If you want to plot the maximum against a from 10 to 14, just use plot(a,M). If you want to plot only against the five values a = [10 ,11, 12 ,13, 14], you can just change the area of interest from 10:0.1:14 to 10:14. If you want to plot the 10th through 14th elements of a and M, you can say plot(a(10:14),M(10:14)).
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