MATLAB: I’m trying to plot the golden ratio to show that it converges

fibonaccigolden ratio

I'm trying to write a matlab script that displays the fibonacci sequence and plots the ratio of succesive members of the series (the golden ratio), 1/1=1; 2/1=2; 3/2=1.5 etc. I already figured out the code to display the fibonacci sequence. I just don't know how to plot the ratio. Here is my code I have so far.

%code
f=[1 1];
x=1;
while f(x) < 10000
f(x+2)=f(x+1)+f(x);
x=x+1;
end
f

Best Answer

Just add a line to calculate the ratio at each step. E.g.,

Initialize prior to the loop:

f_ratio = [1 1];

Then add inside the loop:

f_ratio(x+2) = f(x+2)/f(x+1);

Then after the loop:

plot(f_ratio);

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MATLAB: Can someone give an example of a for loop for this problem?: Find the sum of 30 numbers that increments by 3. The starting number is 4. Thanks!

x = sum(4:3:(4+3*(30-1)))

MATLAB: While loop isn’t working

You have two mistakes

1. while loop should work with a scalar condition, but as far as I know if you use a logical vector it will only enter the loop if all values are true:

% endless loop - as expected
while true
    disp(rand(1));
end
% never enters loop - as expected
while false
    disp(rand(1));
end
% endless loop
while [true true]
    disp(rand(1));
end
% never enters loop

while [false true]
    disp(rand(1));
end
% never enters loop
while [true false]
    disp(rand(1));
end

So when you declared x as a vector 1x50 you booby trapped your loop. just initialize x to the x_0 value

x = x_0;

2. In your loop condition you checked if the value is smaller than the tolerance value instead of larger, so naturally it will never enter the loop unless by luck you started from zero:

while abs(f(x)) > epsilon T % should work

Best Answer

Related Solutions

MATLAB: Can someone give an example of a for loop for this problem?: Find the sum of 30 numbers that increments by 3. The starting number is 4. Thanks!

MATLAB: While loop isn’t working

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