MATLAB: How to use find to cell cell indexing

cell

why does this not work ?

find(grnd_truth_cell{:,1} == 6)

I want to find all of grnd_truth_cell whose 1st column at every row == 6 but matlab tell me Error using == Too many input arguments.

Best Answer

Because as your command line shows,

grnd_truth_cell{:,1}

is a comma-separated list. Enclose it in the [] to make an array that find can operate over--

find([grnd_truth_cell{:,1}]==6)

Related Solutions

MATLAB: Extracting a field name from a cell array in a structure

A = name1.name2.name3.name4;
idx = find(cellfun(@isstruct,A));
i2 = cellfun(@(x)any(strcmp(x,'name5')),cellfun(@fieldnames,A(idx),'un',0));
idx = idx(i2);
out = A(idx)

MATLAB: Conversion to cell from double is not possible

If you want the output to be a cell in the case 2, you have to do this

onset_time_second = cell(ratio_channels,4);
onset_time_second (:, 1) = cellfun(@(x)(findchangepts(x, 'Statistic', 'mean')), beta_cell_second, 'UniformOutput', false)

To help you understand, try this:

 A = num2cell(1:10);
 O = cell(1, 10);
 B = cellfun(@(x) x(1), A); %Returns double matrix
 C = cellfun(@(x) x(1), A, 'un', 0); %Returns cell array
 O(:) = B; %ERROR! Conversion to cell from double is not possible
 O(:) = C; %OKAY!

Best Answer

Related Solutions

MATLAB: Extracting a field name from a cell array in a structure

MATLAB: Conversion to cell from double is not possible

Related Question