MATLAB: How to evaluate integral with given constant

integration

syms x; f = 'h*x'; h =3; int(sym(f))

My code gives (h*x^2)/2

But I want it to evaluate it for h = 3 and then print the answer

Best Answer

Hi,

change the order of your commands

syms x;
h = 3;
f = h*x;
int(sym(f))

gives:

ans =
(3*x^2)/2

Best regards

Stephan

Related Solutions

MATLAB: How to convert Maple Code to Matlab Code

syms x h
basisfunctions = [ (x−h/2)*(x−h) / (0−h/2) / (0−h);
                   (x−0)*(x−h) / (h/2−0) / (h/2−h);
                   (x−0)*(x−h/2) / (h−0) / (h−h/2) ];
A = sym(zeros(3,3);
for i = 1 : 3
  for j = 1 : 3
    A(i,j) = simplify( int( diff(basisfunctions(i,1), x) * ...
                            diff(basisfunctions[j,1],x), x, 0, h ));
  end
end
A

MATLAB: Evaluating constants

The posted code is working without an error. Matlab#s MLint mentions, that ro4 and all gm* variables are not used. But I do get an error message.

What about this:

ANS2 = 8010.837753694346;

Another impression: The accuracy of the output depends on the accuracy of the inputs. Did you analyse the sensitivity of the output to a variation of the inputs already? If accuracy matters, such an analysis is fundamental.

Best Answer

Related Solutions

MATLAB: How to convert Maple Code to Matlab Code

MATLAB: Evaluating constants

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