MATLAB: How to draw circle with radius 1

My question is:

how to draw circle with radius 1 ?

Best Answer

Rad3Over2 = sqrt(3) / 2;
[X Y] = meshgrid(-.2:0.2:1.6);
n = size(X,1);
X = Rad3Over2 * X;
Y = Y + repmat([0 0.5],[n,n/2]);
% Plot the hexagonal mesh, including cell borders
[XV, YV] = voronoi(X(:),Y(:));
plot(XV,YV,'b')
axis equal,
axis([.2 1.2 .2 1])
zoom on ;
hold on
%%Get centers
[V,C] = voronoin([X(:) Y(:)]) ;
xc = cellfun(@(index) mean(V(index,1)),C);
yc = cellfun(@(index) mean(V(index,2)),C);
%%draw circles
th = linspace(0,2*pi) ; r = 0.1 ;
x = r*cos(th) ; y = r*sin(th) ;
for i = 1:length(xc)
    if ~isinf(xc(i))
        xx = x+xc(i) ;
        yy = y+yc(i) ;
        plot(xx,yy,'r')
    end
end

Related Solutions

MATLAB: I need help to plot circle around the points and these points are in a circle. please response

n=10; % number of points that you want
    center = [2 ,2]; % center coordinates of the circle [x0,y0] 

    radius = 10; % radius of the circle

      angle = 2*pi*rand(n,1);
      r = radius*sqrt(rand(n,1));
     X = r.*cos(angle)+ center(1);
     Y = r.*sin(angle)+ center(2);
     plot(X,Y,'.r')
     hold on
     %%Draw circle 
     R = 1. ;  % radius 
     th = linspace(0,2*pi) ;
     for i = 1:length(X)
         x = R*cos(th)+X(i) ;
         y = R*sin(th)+Y(i) ;
         plot(x,y,'b')
     end
     hold on
     center = [2 ,2]; % center coordinates of the circle [x0,y0] 
    radius = 10; % radius of the circle
    angle = 0:.01:2*pi;
    r = radius;
       X = r.*cos(angle)+ center(1);
       Y = r.*sin(angle)+ center(2);
     plot(X,Y,'.b')

MATLAB: How to discover intersecting circles

Try this:

% Create sample data.
numCircles = 10;
xy = rand(numCircles, 2);
radii = 0.1 * rand(numCircles, 1) + 0.1;
viscircles(xy, radii);
% Label them so we know what circle is what.
for k = 1 : numCircles
	text(xy(k, 1), xy(k, 2), num2str(k));
end
axis square;
% See if any intersect
for k = 1 : numCircles
	% Compute the distance between centers.
	distances = sqrt((xy(k, 1) - xy(:, 1)).^2 + (xy(k, 2) - xy(:, 2)) .^2);
	sumOfRadii = radii(k) + radii(:);
	intersectingIndexes = distances < sumOfRadii;
	% Don't compare circle to itself.  Of course that one intersects!
	intersectingIndexes(k) = false;
	% Convert to linear indexes
	intersectingIndexes = find(intersectingIndexes);
	for k2 = 1 : length(intersectingIndexes)
		fprintf('Circle %d intersects with circle #%d.\n', k, intersectingIndexes(k2));
	end
end

You see

Circle 1 intersects with circle #2.

Circle 1 intersects with circle #5.

Circle 1 intersects with circle #7.

Circle 2 intersects with circle #1.

Circle 2 intersects with circle #5.

Circle 3 intersects with circle #7.

Circle 3 intersects with circle #9.

Circle 5 intersects with circle #1.

Circle 5 intersects with circle #2.

Circle 6 intersects with circle #10.

Circle 7 intersects with circle #1.

Circle 7 intersects with circle #3.

Circle 8 intersects with circle #9.

Circle 9 intersects with circle #3.

Circle 9 intersects with circle #8.

Circle 10 intersects with circle #6.

and it's trivial to find out if one circle is completely contained within another. See if you can do it.

Best Answer

Related Solutions

MATLAB: I need help to plot circle around the points and these points are in a circle. please response

MATLAB: How to discover intersecting circles

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