MATLAB: Convert the Mathematica expression to matlab

convert code to matlabconvert mathematica to matlab code

Hello I want to convert the following lines to matlab.But I am unable to do it with matlab to function.Please help..

x[i_]:=x[i]=x[i-1]+h f1[t[i-1],x[i-1],y[i-1],z[i-1]]+1/2 h2 (f1(1,0,0,0)[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,1,0,0)[t[i-1],x[i-1],y[i-1],z[i-1]] f1[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,0,1,0)[t[i-1],x[i-1],y[i-1],z[i-1]] f2[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,0,0,1)[t[i-1],x[i-1],y[i-1],z[i-1]] f3[t[i-1],x[i-1],y[i-1],z[i-1]])

This is implementation of Taylor series.

Best Answer

MAtlab has inbuilt function for Taylor series

doc taylor

http://www.mathworks.com/help/toolbox/symbolic/taylor.html

Related Solutions

MATLAB: Usage Of “goto” for previous lines

Insert this code

test=1;
while test==1
      y(i+1)=y(i)+(0.5*h*(Y(i)+Z(i+1)))
      Y(i+1)=x(i+1)+y(i+1)
      if abs(Y(i+1)-Z(i+1))>0.00000000001
          Z(i+1)=Y(i+1)
          test=1;
      else
          test=0;
      end
end

MATLAB: What is wrong with the code? I have to find value of x(20 sec), y(20 sec) & z(20 sec). The correct answers are: x(20) = 0.704, y(20) = 0.665, z(20) = 0.246.

mistake

Best Answer

Related Solutions

MATLAB: Usage Of “goto” for previous lines

MATLAB: What is wrong with the code? I have to find value of x(20 sec), y(20 sec) & z(20 sec). The correct answers are: x(20) = 0.704, y(20) = 0.665, z(20) = 0.246.

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