Let's say:
A : 4x1 structure classA= Field1 :[1000x1 double], Field2 : [2x1 double], Field3 : [5x1 double], Field4 : [1x1 double]A= Field1 : [1;2;3...;1000], Field2 : [99;11], Field3 : [44;11;33;88;66], Field4 : [77]
Question: How can i convert "structure A" to "double class B" for the last third double ?
_Result_: B=[99;11;44;11;33;88;66;77]
Best Answer