MATLAB: Change the number of the day since specified year to date

datedaynumber

Hi, how to change the day number since 1800 year

for example 86135 (day number since 1800 year) to format 30-10-2035

Thanks

Best Answer

dn = 86135;
datestr(dn+datenum('12-31-1799')); %MATLAB counts from the date "1-1-0000"

See "doc datenum" and "doc datestr" for some more details.

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MATLAB: Please help!!!! Write a function that returns the number of days between dates

days_between_dates = @(month1,day1,year1,month2,day2,year2)...
                         abs(datenum(year1,month1,day1) - datenum(year2,month2,day2));

days_between_dates = @(month1,day1,year1,month2,day2,year2)...
                            abs(diff(datenum([year1,month1,day1;year2,month2,day2])));

use:

>> days_between_dates(10,12,2015,9,5,2016)
ans =
   329
>>

MATLAB: Matlab Busy since four hours

Your method of appending columns to 'Result_matrix' is very time consuming. Also as Geoff points out, your creation of a new 'z' matrix each time in the inner loop is very inefficient. I suggest you alter your code as follows:

   ......
   Result_matrix = zeros(7824,1297); % 1297 = 4*27*12+1
   c = 1;
   for i= 1:4
     u= 7824*(i-1)+1;
     g= u +7823;
     for j= 0:26
       for k= 96:107
         h= 163*j + k;
         S = mlinverse(:,u:g) * linverse(:,h);
         c = c+1;
         Result_matrix(:,c) = S;
       end
     end
   end

This should give you the same result and be considerably faster.

Final note: Do you really want the first column of Result_matrix to be all zeros?

Best Answer

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MATLAB: Please help!!!! Write a function that returns the number of days between dates

MATLAB: Matlab Busy since four hours

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