MATLAB: Basic question again : How plot a finite length rectangular pulse

pulse

Im trying to plot this signal: x(n)=1 for n=2:4 . I tried by rectpuls :

figure
n=2:4;
y=rectpuls(n);
stem (y);

But surprisingly I get 0 for all three samples of y. Is there any other way to do that? (Ive found that if I write y=rectpuls(n)+1 , it works. However I don't want to cheat and manipulate the code!)

Thanks a lot for any help !

Best Answer

n=2:4;
y=ones(1,numel(n))
stem(n,y)

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MATLAB: How to write y(n)=y(n-1)+x(n) in a way to store all values of y from n=1 to n

There are vectorized ways to do this, but using your formula directly:

y = zeros(size(x));
y(1) = something;  % <-- you fill this in, e.g. maybe x(1)?
n = something;  % <-- you fill this in
for k=2:n  % <-- for the rest of the elements through n
    y(k) = y(k-1) + x(k);  % <-- your formula
end

MATLAB: Help plotting a signal pulse

I always define functions similar to ‘unitstep’ as a function:

unitstep = @(t) t >= 0;

This makes it easier to work with. (The argument itself is not important. I used ‘t’ here because that is generally how the step function is defined.)

Second, since:

‘I have u[n] and x[n], but the pulse is "Plot of h[n]" which is just h[n] = u[n] - u[n-3]’

is now straightforward:

h = unitstep(n) - unitstep(n-3);

and you get the plot you want!

It may be necessary for you to tweak some of the rest of your code to work with the function version of ‘unitstep’. That should not be difficult. (I only ran what was necessary to deal with ‘h’ and plot it, since that appears to be where the problem is.)

Best Answer

Related Solutions

MATLAB: How to write y(n)=y(n-1)+x(n) in a way to store all values of y from n=1 to n

MATLAB: Help plotting a signal pulse

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