MATLAB: Anonymous function from for loop

Question

Hello, I am having trouble creating an anonymous function matrix using a for loop. My code looks like this:

 n=4; %Or w/e number. Could be 100.
 for i = 1:n
    f{i,1} = @(x) (x.^i).*(1-x)
 end

The output is this:

f =

    @(x)(x.^i).*(1-x)
    @(x)(x.^i).*(1-x)
    @(x)(x.^i).*(1-x)
    @(x)(x.^i).*(1-x)

The problem is that the "i" is not changing. It should look like this:

f =

    @(x)(x.^1).*(1-x)
    @(x)(x.^2).*(1-x)
    @(x)(x.^3).*(1-x)
    @(x)(x.^4).*(1-x)

Any ideas? Also, I will later have to take the derivative of each row. Is there a simple way to do it? Like this maybe:

 derivative(1) = der(f{1})
 derivative(2) = der(f{2})

Thanks in advance!

Answer 1

Although it is showing i, as the variable, this is actually hardwired to the numeric value.

for ii = 1:n
  feval(f{ii},pi)
end

Yields:

ans =
 -6.7280
ans =
-21.1367
ans =
-66.4028
ans =
-208.6106

In order to see the value for the captured variables in the anonymous function, you can use functions

fns = functions(f{1})
fns.workspace{1}

In order to take the derivative analytically, I would use Symbolic Math and syms

syms x ix
f = (x.^i).*(1-x)
    f =
       -x^4*(x - 1)
diff(f,x)
    ans =
       - 4*x^3*(x - 1) - x^4