I have a small algebra problem
If the sum of two consecutive integers is $x$, what would be their product?
I've made equation.$$n+(n+1)=x$$
But, don't understand how to find their sum.
algebra-precalculuslinear algebra
I have a small algebra problem
If the sum of two consecutive integers is $x$, what would be their product?
I've made equation.$$n+(n+1)=x$$
But, don't understand how to find their sum.
Best Answer
$$n + (n + 1) = x \implies n = \frac{x - 1}{2}$$
Then $$n(n + 1) = \left(\frac{x - 1}{2}\right) \left(\frac{x - 1}{2} + 1\right) = \left(\frac{x - 1}{2}\right)\left(\frac{x + 1}{2}\right) = \frac{x^2 - 1}{4}.$$